2x^2+20x=112

Solution for 2x^2+20x=112 equation:

Simplifying
2x2 + 20x = 112

Reorder the terms:
20x + 2x2 = 112

Solving
20x + 2x2 = 112

Solving for variable 'x'.

Reorder the terms:
-112 + 20x + 2x2 = 112 + -112

Combine like terms: 112 + -112 = 0
-112 + 20x + 2x2 = 0

Factor out the Greatest Common Factor (GCF), '2'.
2(-56 + 10x + x2) = 0

Factor a trinomial.
2((-14 + -1x)(4 + -1x)) = 0

Ignore the factor 2.
Subproblem 1
Set the factor '(-14 + -1x)' equal to zero and attempt to solve:

Simplifying
-14 + -1x = 0

Solving
-14 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '14' to each side of the equation.
-14 + 14 + -1x = 0 + 14

Combine like terms: -14 + 14 = 0
0 + -1x = 0 + 14
-1x = 0 + 14

Combine like terms: 0 + 14 = 14
-1x = 14

Divide each side by '-1'.
x = -14

Simplifying
x = -14
Subproblem 2
Set the factor '(4 + -1x)' equal to zero and attempt to solve:

Simplifying
4 + -1x = 0

Solving
4 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + -1x = 0 + -4

Combine like terms: 4 + -4 = 0
0 + -1x = 0 + -4
-1x = 0 + -4

Combine like terms: 0 + -4 = -4
-1x = -4

Divide each side by '-1'.
x = 4

Simplifying
x = 4
Solution
x = {-14, 4}